Finding Items in a List

     Now that you know enough about Python, it's about time we get back to lists.
     What if we have a really long list, and we want to find an item in it? To search a list, we have to use the in function.
     You probably got rid of the family list from the other articles, so let's make a different one.

numbers=['1', '2', '3', '4', '5', '6']

     Let's say we don't know if the number 3 is in the list. This is where the function comes in:

if '3' in numbers:
    print("3 is in the numbers.")
else:
    print("3 is not in the numbers.")

     You should get "3 is in the numbers." Let's try this again, but with a number that really isn't in the list.

if '10' in numbers:
    print("10 is in the numbers.")
else:
    print("10 is not in the numbers.")

     You should get "10 is not in the numbers." The in statement basically debates if an item being in the list is true or false.
     There's even a kinda faster way to do this:

'1' in numbers

     This should appear:

True

     But if you do a false one:

'99' in numbers

False

     So if you do a quick thing like that, it just says "True" or "False."
     You can even do a group of numbers at a time, like this:

'1' in numbers and '2' in numbers and '3' in numbers and '4' in numbers and '5' in numbers

True

     But if 1 number is not in the list...

'1' in numbers and '2' in numbers and '7' in numbers

False

     There you have it. We can even remove items we found in the list, like this:

if '6' in numbers:
    numbers.remove('6')

print(numbers)

['1', '2', '3', '4', '5']

     You can even remove a number if a different one is in the list.

if '1' in numbers:
    numbers.remove('5')

print(numbers)

['1', '2', '3', '4']

     Now that we have that covered, what if we want to find an item's index?

numbers.extend(['5', '6'])

     (I had to put the numbers back in since I was running out.)

print(numbers.index('5'))

4

     That is the index of the number, not the number itself (duh). You can do the same thing with index() that you can do with remove().

if '6' in numbers:
    print(letters.index('6'))

5

     You can also do the other thing I explained with remove(), if a certain number is in the list, then remove a different number.
     Well, that's all there is to searching a list. That was a lot to cover in this article, wasn't it?

Randint

     Another function I have deciphered is random.randint().
     First, you have to type:

import random

     Now, what does randint mean? It actually means random integer. Now, type this:

print(random.randint(1, 12))

     The output should be a random number. Keep typing the same thing, and you'll notice that the number keeps changing.
     You can also use random.randint with lists! Type this:

list=["Hi", "Bye", "Die"]
listInt=random.randint(0, 2)
print(list[listInt])

     You should get one of the items from the list. Remember, lists start with 0, not 1. You tell Python to print list, but then listInt in the square brackets tells it to take a random item from the list and print it. What if we did one that's out of range?

listInt=random.randint(0, 15)
print(list[listInt])

Traceback (most recent call last):
  File "<pyshell#10>", line 1, in <module>
    print(list[listInt])
IndexError: list index out of range

     So, it has to be the limit of items in the list.
     That's all I know about random.randint, so... That's it.